正确答案：
A
解析：
Since the length of each side of the figure is 1 unit, AB + BC + CD +DE + EA = 5. Therefore, each time a point starts and ends at vertex A, the point moves 5 units each time a point starts and ends at vertex A, the point moves 5 units or a multiple of 5 units. Since 715/5 = 143 with no remainder, a point that starts at vertex A and moves a distance of 715 units along each side of the figure will go around the entire figure exactly 143 times, so it will end up at vertex A.
